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Re: [xsl] Sorting nested steps

2013-07-31 07:40:32
At 2013-07-31 08:30 -0400, Rick Quatro wrote:
I have a series of nested steps that I want to reverse sort at each level.
Here is what I am starting with:
...
This is what I want to get:
...
My steps could be nested up to five levels, so I tried to call a template
recursively, but it is not giving me exactly what I want.

When I think of recursion, I try to think of how applying templates would work ... and the end result is really quite compact.

I hope the code below helps.

. . . . . . . Ken

T:\ftemp>type rick.xml
<?xml version="1.0"?>
<steps>
    <step>A
        <step>(1)</step>
        <step>(2)
            <step>(a)</step>
            <step>(b)</step>
            <step>(c)</step>
        </step>
        <step>(3)</step>
    </step>
    <step>B</step>
    <step>C</step>
</steps>
T:\ftemp>xslt rick.xml rick.xsl
<?xml version="1.0" encoding="utf-8"?>
<steps>
   <step>C</step>
   <step>B</step>
   <step>A
        <step>(3)</step>
      <step>(2)
            <step>(c)</step>
         <step>(b)</step>
         <step>(a)</step>
      </step>
      <step>(1)</step>
   </step>
</steps>
T:\ftemp>type rick.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="https://www.w3.org/1999/XSL/Transform";
  version="1.0">

<xsl:output indent="yes"/>

<xsl:template match="steps | step">
  <xsl:copy>
    <xsl:apply-templates select="text()[normalize-space()]"/>
    <xsl:apply-templates select="step">
      <xsl:sort select="position()" order="descending"/>
    </xsl:apply-templates>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>

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