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Re: [xsl] creating and populating string

2013-07-10 08:50:07
Hi
I think the question was representaive enough however it is often the 'human' 
naure (me too) to give less but get much.....
Because the home work was causal I used the xsl:choose for that:

<xsl:variable name="buf" select=" concat('0000000000000000000000000', 
arf:elmentId)"/>
<xsl:variable name="systemId" select="arf:elmentId"/>
<xsl:choose>
<xsl:when test="string-length($systemId) &lt; 25">
<xsl:value-of select="concat(substring($buf, ( (string-length($buf)+1) - 25), 
string-length($buf)),arf:srvDate)"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="concat(substring(arf:elmentId, 
string-length(arf:elmentId) - 16), arf:srvDate)"/>
</xsl:otherwise>
</xsl:choose>
    
Thanks
Henry
----- Ursprüngliche Message -----
Von: Liam R E Quin <liam(_at_)w3(_dot_)org>
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
CC: 
Gesendet: 18:29 Dienstag, 9.Juli 2013
Betreff: Re: [xsl] creating and populating string

On Tue, 2013-07-09 at 16:03 +0100, henry human wrote:
Hi
I have a string, string1 which could be  1,2,3,..20..100 characters
long
I will only the last 10 characters of the string1 to build string2 and
if string1 shorter than 10 characters string2 should be populated with
'0'

You don't actually ask a question but I'm guessing you want to know how
to use string-length(), substring() and subtraction?

Here's one way to do what I think you are asking for, padding with
leading zeros:

<xsl:variable name="s" select=" concat('0000000000', $input) " />
<xsl:value-of select="substring($s, 1 + string-length($s) - 10, 10)" />

Note, If this is homework, please at least take the time to understand
the solution - maybe use pencil and paper... assuming it does work - I
didn't try it.

Liam

-- 
Liam Quin - XML Activity Lead, W3C, https://www.w3.org/People/Quin/
Pictures from old books: https://fromoldbooks.org/
Ankh: irc.sorcery.net irc.gnome.org freenode/#xml


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